A pipe 20 cm long is closed at one end. | Class 11 Physics Chapter Waves, Waves NCERT Solutions

Question:

A pipe 20 cm long is closed at one end. Which harmonic mode of the pipe is resonantly excited by a 430 Hz source? Will the same source be in resonance with the pipe if both ends are open? (Speed of sound in air is 340 m s-1).

Answer:

First (Fundamental); No

Length of the pipe, l = 20 cm = 0.2 m

Source frequency = nth normal mode of frequency, Vn = 430 Hz

Speed of sound, v = 340 m/s

In a closed pipe, the nth normal mode of frequency is given by the relation:

V=  (2n -1) v / 4l                    ; n is an integer = 0, 1, 2, 3...

430 = (2n-1) 340 / (4x0.2)

2n -1  =  (430 x 4 x 0.2) / 340 =  1.01

2n = 2.01

n ≈ 1

Hence, the first mode of vibration frequency is resonantly excited by the given source.

In a pipe open at both ends, the nth mode of vibration frequency is given by the relation:

Vn    =  nv  / 2l

n = 2lV/ v

 = 2 x 0.2 x 430 / 340  =  0.5

Since the number of the mode of vibration (n) has to be an integer, the given source does not produce a resonant vibration in an open pipe.


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 17: A pipe 20 cm long is closed at one end. Which harmonic mode of the pipe is resonantly excited by a 4....