Two sitar strings A and B playing the no | Class 11 Physics Chapter Waves, Waves NCERT Solutions

Question:

Two sitar strings A and B playing the note 'Ga' are slightly out of tune and produce beats of frequency 6 Hz. The tension in the string A is slightly reduced and the beat frequency is found to reduce to 3 Hz. If the original frequency of A is 324 Hz, what is the frequency of B?

Answer:

Frequency of string A, fA = 324 Hz

Frequency of string B = fB

Beat's frequency, n = 6 Hz

Beat's frequency is given as:

n = l fA +- fB l

6 =  324 +- fB

fB  = 330 Hz or 318 Hz

Frequency decreases with a decrease in the tension in a string. This is because frequency is directly proportional to the square root of tension. It is given as:

v ∝ Underroot T

Hence, the beat frequency cannot be 330 Hz

∴ fB = 318 Hz


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 18: Two sitar strings A and B playing the note 'Ga' are slightly out of tune and produce beats o....