For the wave described in Exercise 15.8, | Class 11 Physics Chapter Waves, Waves NCERT Solutions

Question:

For the wave described in Exercise 15.8, plot the displacement (y) versus (t) graphs for x = 0, 2 and 4 cm. What are the shapes of these graphs? In which aspects does the oscillatory motion in travelling wave differ from one point to another: amplitude, frequency or phase?

Answer:

Given, y(x, t) =3 sin (36t +0.018x + π/4) . . . . . . . . . . . ( 1 )

For x= 0, the equation becomes :

y( 0, t ) =3 sin ( 36t +0 + π/4 ) . . . . . . . . . . . ( 2 )

Also, ω = 2 π/t = 36 rad/s-1

therefore t = π/18 secs.

Plotting the displacement (y) vs. (t) graphs using different values of t listed below:

t (s) 0 T/8 2T/8 3T/8 4T/8 5T/8 6T/8 7T/8
y (cm) 3√2 / 2 3 3√2 / 2 0 -3√2 / 2 -3 -3√2 / 2 0

Similarly graphs are obtained for x = 0, x = 2 cm, and x = 4 cm.

The oscillatory motion in the travelling wave is different from each other only in terms of phase. Amplitude and frequency are invariant for any change in x.

The y-t plots of the three waves are shown in the given figure:


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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: For the wave described in Exercise 15.8, plot the displacement (y) versus (t) graphs for x = 0, 2 an....