A hockey ball of mass 200 g travelling at 10 m s-1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s-1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.
Mass of the hockey ball, m = 200 g = 200 / 1000 = 0.2 kg
Initial velocity, v1 = 10 m/s
Initial momentum = mv1
Final velocity, v2 = −5 m/s
Final momentum = mv2
Change in momentum = mv1 − mv2 = m(v1 - v2)
= 0.2 [10 − (−5)] = 0.2 (15) = 3.0 kg m/s
Hence, the change in momentum of the hockey ball is 3 kg m/s.
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 3 , Question 13: A hockey ball of mass 200 g travelling at 10 m s-1 is struck by a hockey stick so as to return ....
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