A car starts from rest and moves along t | Class 9 Science Chapter Motion, Motion NCERT Solutions

Question:

A car starts from rest and moves along the x-axis with constant acceleration 5 m s–2 for 8 seconds. If it then continues with constant velocity, what distance will the car cover in 12 seconds since it started from the rest?

Answer:

The velocity attained in 8 seconds is given by

V = u+at
v = 0+5*8
v = 40m/s

The distance travelled in the first 8 sec = S1 = ut + 1/2 at2 = 0 + 1/2 x 5 x 64 = 160 m

The distance travelled in the last 4 sec with const. speed = S2 = vt = 40 x 4 = 160 m 

So the total distance travelled by car in 12 sec = 160 + 160 = 320m


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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 0 , Question 15: A car starts from rest and moves along the x-axis with constant acceleration 5 m s–2 for 8 sec....