An electron moving with a velocity of 5 × 104 m s-1 enters into a uniform electric field and acquires a uniform acceleration of 104 m s–2 in the direction of its initial motion.
(i) Calculate the time in which the electron would acquire a velocity double of its initial velocity.
(ii) How much distance the electron would cover in this time?
Given initial velocity of electron, u = 5 x 10 ^4 m/s
Acceleration, a = 10^4 m/s^2
(i) Using first equation of motion,
Final velocity, v = 2u
v = u + at
2u = u + at
t = u/a = 5 s
(ii) Distance travelled in this time interval be s using 2nd equation of motion
s = ut + ½ at^2
s = 5 x 10^4 x 5 + ½ x 10^4 x 5^2
s = 37.5 x 10^4 m
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 0 , Question 22: An electron moving with a velocity of 5 × 104 m s-1 enters into a uniform electric field and a....
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