Velocity versus time graph of a ball of mass 50 g rolling on a concrete floor is shown in Fig. 9.1. Calculate the acceleration and frictional force of the floor on the ball.
Given, mass (m) = 50 g = 50/1000 = 0.05 kg
Initial velocity, u = 80 m/s
Final velocity, v = 0 m/s
Time taken, t = 8 sec
From first equation of motion, v = u + at
a = (v - u) / t
a = ( 0 - 80 ) / 8 = - 10 m/s^2
Now frictional force of the floor on the ball ( F ) = ma = 0.05 x (-10) = - 0.5 N (negative sign shows against the direction of motion)
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 0 , Question 14: Velocity versus time graph of a ball of mass 50 g rolling on a concrete floor is shown in Fig. 9.1. ....
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