A boy is moving on a straight road against a frictional force of 5 N. After travelling a distance of 1.5 km he forgot the correct path at a round about (Fig. 11.1) of radius 100 m. However, he moves on the circular path for one and half cycle and then he moves forward upto 2.0 km. Calculate the work done by him.
Frictional force, F = 5 N
∴ Work done by boy = Force x Total distance covered
Total distance covered =1.5km + 1.5km ( 2π x 100 m ) + 2km = 1500 + 1500(2π + 100) + 2000 = 1500 + 942 + 2000 = 4442 m (4.442 km)
= 5 N × 4.442 km
= 5 N × 4442m = 22210J
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Welcome to the NCERT Solutions for Class 9 Science - Chapter . This page offers a step-by-step solution to the specific question from Excercise 0 , Question 12: A boy is moving on a straight road against a frictional force of 5 N. After travelling a distance of....
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