SELECT * FROM question_mgmt as q WHERE id=1191 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=44 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

Consider the following species:

N3–, O2–, F–, Na+, Mg2+ and Al3+

(a) What is common in them?

(b) Arrange them in the order of increasing ionic radii.

Answer:

(a) Each of the given species (ions) has the same number of electrons (10 electrons). Hence, the given species are isoelectronic, i.e

N3- has 7+3 = 10 electrons

O2-  has  8+2= 10 electrons

F- has 9+1 = 10 electrons

Na+ has 11-1 = 10 electrons

Mg2+  has 12-2 = 10 electrons

Al3+ has 13-3= 10 electrons

(b) The ionic radii of isoelectronic species increases with a decrease in the magnitudes of nuclear charge.

The arrangement of the given species in order of their increasing nuclear charge is as follows:

N3– < O2– < F– < Na+ < Mg2+ < Al3+

Nuclear charge = +7 +8 +9 +11 +12 +13

Therefore, the arrangement of the given species in order of their increasing ionic radii is as follows:

Al3+ < Mg2+ < Na+ < F– < O2– < N3–


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