SELECT * FROM question_mgmt as q WHERE id=1926 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=64 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.

Answer:

[Mn(H2O)6]2+ [Mn(CN)6]4-
Mn is in the +2 oxidation state. Mn is in the +2 oxidation state.
The electronic configuration is d5. The electronic configuration is d5.
The crystal field is octahedral. Water is a weak field ligand. Therefore, the arrangement of the electrons in [Mn(H2O)6]2+ is t2g3eg2.

The crystal field is octahedral. Cyanide is a strong field ligand. Therefore, the arrangement of the electrons in [Mn(CN)6]4- is T2g5eg0.
Hence, hexaaquo manganese (II) ion has five unpaired electrons while hexacyano ion has only one unpaired electron.

 


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