SELECT * FROM question_mgmt as q WHERE id=1926 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=64 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacyanoion contains only one unpaired electron. Explain using Crystal Field Theory.
[Mn(H2O)6]2+ | [Mn(CN)6]4- |
Mn is in the +2 oxidation state. | Mn is in the +2 oxidation state. |
The electronic configuration is d5. | The electronic configuration is d5. |
The crystal field is octahedral. Water is a weak field ligand. Therefore, the arrangement of the electrons in [Mn(H2O)6]2+ is t2g3eg2. |
The crystal field is octahedral. Cyanide is a strong field ligand. Therefore, the arrangement of the electrons in [Mn(CN)6]4- is T2g5eg0. |
Hence, hexaaquo manganese (II) ion has five unpaired electrons | while hexacyano ion has only one unpaired electron. |
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