SELECT * FROM question_mgmt as q WHERE id=1788 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=58 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)
The conductivity of 0.20 M solution of KCl at 298 K is 0.0248 Scm-1. Calculate its molar conductivity.
Given, k = 0.0248 S cm - 1
c = 0.20 M
Molar conductivity, Am = (k x 1000) / c
= 0.0248 x1000 / 0.20
124 Scm2 mol - 1
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