SELECT * FROM question_mgmt as q WHERE id=1797 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=58 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Electrochemistry calculate the emf of the cell in which the followi

Question:

Calculate the emf of the cell in which the following reaction takes place:

Ni(s) + 2Ag+ (0.002 M) → Ni2+ (0.160 M) + 2Ag(s)

Given that Eøcell = 1.05 V

Answer:

Applying Nernst equation we have:

= 1.05 - 0.02955 log 4 × 104

= 1.05 - 0.02955 (log 10000 + log 4)

= 1.05 - 0.02955 (4 + 0.6021)

= 0.914 V


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