SELECT * FROM question_mgmt as q WHERE id=1801 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=58 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Electrochemistry consider the reaction cr2 o72 14h 6e n

Question:

Consider the reaction:

Cr2 O72- + 14H+ + 6e- → Cr3+ + 8H2O 

What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2 O72-?

Answer:

The given reaction is as follows:

Cr2 O72- + 14H+ + 6e- → Cr3+ + 8H2O 

Therefore, to reduce 1 mole of Cr2 O72-, the required quantity of electricity will be:

= 6 F

= 6 × 96487 C

= 578922 C


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