SELECT * FROM question_mgmt as q WHERE id=2821 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=48 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Equilibrium at a certain temperature and total pressure of 105

Question:

At a certain temperature and total pressure of 105 Pa, iodine vapour contains 40% by volume of I atoms

I2(g)    ↔    2l (g)

Calculate Kp for the equilibrium.

Answer:

Partial pressure of I atoms,

pI  =  ptotal x 40/100

    =  105 x 40/100 

    =  4 x 104 Pa 

Partial pressure of I2 molecules,

pI 2   =  ptotal x 60/100

       =  105 x 60/100 

       =  6 x 104 Pa 

Now, for the given reaction,

Kp  = (pI)2  / pI2

     =  (4 x 104 ) 2 Pa2  / 6 x 104 Pa

     =  2.67 x 104 Pa

 

 

 


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