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Question:

For the following equilibrium, Kc = 6.3 × 1014  at 1000 K

NO (g) + O3 (g) ↔ NO2 (g) + O2 (g)

Both the forward and reverse reactions in the equilibrium are elementary bimolecular reactions. What is Kc, for the reverse reaction?

Answer:

It is given that Kc for the forward reaction is 6.3 × 1014  

Then, Kc  for the reverse reaction will be,

K’c  = 1 / Kc

     = 1 /  6.3 × 1014  

     = 1.59 x 10-15


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