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Class 11
Chemistry
Equilibrium
a sample of pure pcl5 was introduced into an evacu...

Question:
A sample of pure PCl5 was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl5 was found to be 0.5 × 10^–1 mol L^–1. If value of Kc is 8.3 × 10^–3, what are the concentrations of PCl₃ and Cl₂ at equilibrium?

PCl₅ (g) ↔ PCl₃ (g) + Cl₂(g)

Answer:

Let the concentrations of both PCl₃ and Cl₂ at equilibrium be x molL^-1. The given reaction is:

PCl₅ (g) ↔ PCl₃ (g) + Cl₂(g)

at equilibrium 0.5x10^-1molL^-1 xmolL^-1 xmolL^-1

it is given that the value of equilibrium constant, Kc is 8.3x10^–3

Now we can write the expression for equilibrium as:

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