SELECT * FROM question_mgmt as q WHERE id=3076 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=48 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Equilibrium the ph of a sample of vinegar is 3 76 calculate t

Question:

The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.

Answer:

Given that:

pH = 3.76

It is known that,

pH = -log [H+]

⇒  log [H+]  = -pH

⇒ [H+] = antilog (-pH)

          = antilog(-3.76)

          = 1.74x10-4 M

Hence, the concentration of hydrogen ion in the given sample of vinegar is 1.74 × 10-4 M.


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='9' AND ex_no!=0 AND status=1 and id!=3076 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='9' AND ex_no!=0 AND status=1 and id!=3076 ORDER BY last_viewed_on desc limit 0,10

Comments

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  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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  • Answered by Ekta Mehta
  • 4 months ago

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