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Class 11
Chemistry
Equilibrium
the ionization constant of propanoic acid is 1 32...

Question:
The ionization constant of propanoic acid is 1.32 x 10^-5. Calculate the degree of ionization of the acid in its 0.05M solution and also its pH. What will be its degree of ionization if the solution is 0.01M in HCl also?

Answer:

Let the degree of ionization of propanoic acid be α.

Then, representing propionic acid as HA, we have:

HA + H₂O ↔ H₃O⁺ + A^-

(0.05-0.0α) ≈ 0.05 0.05α 0.05α

K_a = [H₃O⁺] [A^-] / [HA]

= (0.05α)(0.05α) / 0.05

= 0.05 α²

Then, [H₃O⁺] = 0.05α = 0.05 x 1.63 x 10^-2 = Kb . 15 x 10^-4 M

∴ pH = 3.09

In the presence of 0.1M of HCl, let α' be the degree of ionization.

Then, [H₃O⁺] = 0.01

[A^-] = 0.05α'

[HA] = 0.05

Ka = 0.01 x 0.05α' / 0.05

⇒ 1.32 x 10^-5 = 0.1 α'

α' = 1.32 x 10^-3

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Question:
The ionization constant of propanoic acid is 1.32 x 10^-5. Calculate the degree of ionization of the acid in its 0.05M solution and also its pH. What will be its degree of ionization if the solution is 0.01M in HCl also?

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Question: The ionization constant of propanoic acid is 1.32 x 10-5. Calculate the degree of ionization of the acid in its 0.05M solution and also its pH. What will be its degree of ionization if the solution is 0.01M in HCl also?

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Question:
The ionization constant of propanoic acid is 1.32 x 10^-5. Calculate the degree of ionization of the acid in its 0.05M solution and also its pH. What will be its degree of ionization if the solution is 0.01M in HCl also?