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Class 11
Chemistry
Redox Reactions
justify giving reactions that among halogens fluo...

Question:
Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.

Answer:

F₂can oxidize Cl^- to Cl₂, Br^- to Br₂, and I^- to I₂ as:

F_2(aq) + S₂cl^-_(s) → 2F^-_(aq) + Cl _(g)

F_2(aq) + 2Br^-_(aq) → 2F^-_(aq) + Br_2(l)

F_2(aq) + 2l^-_(aq)→ 2F^-_(aq) + 1_2(s)

On the other hand, Cl₂, Br₂, and I₂ cannot oxidize F^- to F₂. The oxidizing power of halogens increases in the order of I₂ < Br₂ < Cl₂ < F₂. Hence, fluorine is the best oxidant.

HI and HBr can reduce H₂SO₄ to SO₂, but HCl and HF cannot. Therefore, HI and HBr are stronger reductants than HCl and HF.

2HI + H₂SO₄ → l₂ + SO₂ + 2H₂O

2HBr + H₂SO₄ → Br₂ + SO₂ + 2H₂O

Again, I^- can reduce Cu²⁺ to Cu⁺, but Br^- cannot.

4l^-_(aq) + 2Cu²⁺_(aq) → Cu₂l_2(s) + l²_(aq)

Hence, hydroiodic acid is the best reductant among hydrohalic compounds.

Thus, the reducing power of hydrohalic acids increases in the order of HF < HCl < HBr < HI.

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Question:
Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.

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Question: Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.

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Question:
Justify giving reactions that among halogens, fluorine is the best oxidant and among hydrohalic compounds, hydroiodic acid is the best reductant.