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determine the empirical formula of an oxide of iro...

Question:
Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass.

Answer:

Empirical formula of a compound may be defined as the formula which gives the simplest whole number ratio of the atoms of various elements present in one molecule of the compound.

Form the available data Percentage of iron = 69.9

Percentage of oxygen= 30.1 Total percentage of iron & oxygen= 69.9+30.1= 100%

Step 1 calculation of simplest whole number ratios of the elements

Element	Percentage	Atomic mass	Atomic ratio	Simplest ratio	Simplest whole no ratio
Fe	69.9	55.84	69.9/55.84=1.25	1.25= 1	2
O	30.1	16	30.1/16 = 1.88	1.88=1.5	3

Step 2 writing the empirical formula of the compound

The empirical formula of the compound = Fe₂ O₃

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Question:
Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass.

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Question:
Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass.