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Class 11
Chemistry
States of Matter
pressure of 1 g of an ideal gas a at 27 deg c is...

Question:
Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses.

Answer:

Mass of gas A , W_A = 1g

Mass of gas B, W_B= 2g

Pressure exerted by the gas A = 2 bar

Total pressure due to both the gases = 3 bar

In this case temperature & volume remain constant

Now if M_A & M_B are molar masses of the gases A & B respectively,therefore

p_A V= W_A RT/M_A & P_total V = (W_A/M_A + W_B/ M_B) RT

= 2 X V = 1 X RT/M_A& 3 X V = (1/M_A + 2/M_B)RT

From these two equations, we get

3/2 = (1/M_A + 2/M_B) / (1 /M_A) = (M_B + 2M_A) / M_B

This result in 2M_A/ M_B = (3/2) -1 = ½

OR M_B = 4M_A

Thus, a relationship between the molecular masses of A and B is given by

4M_A = M_B

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Question:
Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses.

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Question: Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses.

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Question:
Pressure of 1 g of an ideal gas A at 27 °C is found to be 2 bar. When 2 g of another ideal gas B is introduced in the same flask at same temperature the pressure becomes 3 bar. Find a relationship between their molecular masses.