SELECT * FROM question_mgmt as q WHERE id=1255 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=43 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Structure of Atom yellow light emitted from a sodium lamp has a wave

Question:

Yellow light emitted from a sodium lamp has a wavelength (λ) of 580 nm. Calculate the frequency (ν) and wave number () of the yellow light.

Answer:

Here λ = 580 nm(given)

We have to find out ν & 

Therefore from the equation  we can write,

Where, ν = frequency of yellow light

c = velocity of light in vacuum = 3 × 108 m/s

λ = wavelength of yellow light = 580 nm = 580 × 10–9 m

Substituting the values in we get

Thus, frequency of yellow light emitted from the sodium lamp

= 5.17 × 1014 s–1

Wave number = it is defined as the number of wavelengths which can be accommodated in 1cm length along the direction of propagation.

Wave number of yellow light is given by the equation

We have λ = 580 nm(given),putting the value in the equation we get

 


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SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='9' AND ex_no!=0 AND status=1 and id!=1255 ORDER BY last_viewed_on desc limit 0,10

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