SELECT * FROM question_mgmt as q WHERE id=1303 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=43 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

If the photon of the wavelength 150 pm strikes an atom and one of its inner bound electrons is ejected out with a velocity of 1.5 × 107 ms–1, calculate the energy with which it is bound to the nucleus.

Answer:

Energy of incident photon (E) is given by,

 

= 10.2480 × 10–17 J

= 1.025 × 10–16 J

Energy with which the electron was bound to the nucleus

= 13.25 × 10–16 J – 1.025 × 10–16 J

= 12.225 × 10–16 J

 = 12.225 × 10–16 J/1.602 x10-19 eV

= 7.63x103eV


< Previous Question

Next Question >

SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='9' AND ex_no!=0 AND status=1 and id!=1303 ORDER BY views desc, last_viewed_on desc limit 0,10

  • Popular questions of class 11 Chemistry

SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='9' AND ex_no!=0 AND status=1 and id!=1303 ORDER BY last_viewed_on desc limit 0,10

  • Recently Viewed Questions of Class 11 Chemistry

Comments

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

Comment(s) on this Question


Important links

Quick Links

Resources

Support