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Class 11
Chemistry
The p Block Elements
consider the compounds bcl3 and ccl4 how will th...

Question:
Consider the compounds, BCl₃ and CCl₄. How will they behave with water? Justify.

Answer:

Being a Lewis acid, BCl₃ readily undergoes hydrolysis. Boric acid is formed as a result.

BCl₃ + 3H₂O → 3HCl + B(OH)₃

CCl₄ completely resists hydrolysis. Carbon does not have any vacant orbital. Hence, it cannot accept electrons from water to form an intermediate. When CCl₄ and water are mixed, they form separate layers.

CCl4 + H₂O → No reaction

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Question:
Consider the compounds, BCl₃ and CCl₄. How will they behave with water? Justify.

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Question: Consider the compounds, BCl3 and CCl4. How will they behave with water? Justify.

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Question:
Consider the compounds, BCl₃ and CCl₄. How will they behave with water? Justify.