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Class 12
Chemistry
The Solid State
silver crystallises in fcc lattice if edge length...

Question:
Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10^-8cm and density is 10.5 g cm^-3, calculate the atomic mass of silver.

Answer:

From the equation, density = ZxM/a³ x N₀, we get

M = ρ x a³ x N₀/Z …………………………………1

Placing the values in equation 1,

WE GET M= 10.5 x (4.07 x10^-8)³ x 6.022 x 10²³/4

= 106.6 gmol^-1

= Therefore, atomic mass of silver = 106.6 gmol^-1

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Question:
Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10^-8cm and density is 10.5 g cm^-3, calculate the atomic mass of silver.

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Question: Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10-8cm and density is 10.5 g cm-3, calculate the atomic mass of silver.

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Question:
Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10^-8cm and density is 10.5 g cm^-3, calculate the atomic mass of silver.