SELECT * FROM question_mgmt as q WHERE id=1743 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=56 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

Silver crystallises in fcc lattice. If edge length of the cell is 4.07 x 10-8cm and density is 10.5 g cm-3, calculate the atomic mass of silver.

Answer:

From the equation, density = ZxM/a3 x N0, we get

M = ρ x a3 x N0/Z …………………………………1

Placing the values in equation 1,

WE GET M= 10.5 x (4.07 x10-8)3 x 6.022 x 1023/4

= 106.6 gmol-1

= Therefore, atomic mass of silver = 106.6 gmol-1


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