SELECT * FROM question_mgmt as q WHERE id=1751 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=56 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry The Solid State ferric oxide crystallises in a hexagonal close pac

Question:

Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

Answer:

There are one octahedral hole for each atom in hexagonal close packed arrangement. If the no. of oxide ions per unit cell = 1.

   then no. of fe3+ ions = 2/3 x octahedual holes 

            = 2/3 x 1 = 2/3

   formula of the compound = fe2/3 O1 or fe2O3


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