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ferric oxide crystallises in a hexagonal close pac...

Question:
Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

Answer:

There are one octahedral hole for each atom in hexagonal close packed arrangement. If the no. of oxide ions per unit cell = 1.

then no. of fe³⁺ions = 2/3 x octahedual holes

= 2/3 x 1 = 2/3

formula of the compound = fe_2/3O₁or fe₂O₃

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Question:
Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

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Question: Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.

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Question:
Ferric oxide crystallises in a hexagonal close-packed array of oxide ions with two out of every three octahedral holes occupied by ferric ions. Derive the formula of the ferric oxide.