SELECT * FROM question_mgmt as q WHERE id=1753 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=56 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry The Solid State gold atomic radius 0 144 nm crystallises in a

Question:

Gold (atomic radius = 0.144 nm) crystallises in a face-centred unit cell. What is the length of a side of the cell?

Answer:

We know, for a fcc unit cell,radius of atom

r = a/2√2

Or

a = 2r√2

By putting the values of r &√2 we get

a = 2 x 0.144 x 1.414 = 0.407nm


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