SELECT * FROM question_mgmt as q WHERE id=2791 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=47 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED)

Question:

The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are, –890.3 kJ mol–1  , –393.5 kJ mol–1, and –285.8 kJ mol–1 respectively. Enthalpy of formation of CH4(g) will be

(i) –74.8 kJ mol–1

(ii) –52.27 kJ mol–1

(iii) +74.8 kJ mol–1

(iv) +52.26 kJ mol–1

Answer:

According to the question,

Thus, the desired equation is the one that represents the formation of CH4(g) i.e.,

[-393.5 + 2(-285.8) - (-890.3)] kJ Mol-1

= -74.8 kJ Mol-1

So,Enthalpy of formation of CH4(g) is -74.8 kJ Mol-1

That means answer is (i).


< Previous Question

Next Question >

SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='9' AND ex_no!=0 AND status=1 and id!=2791 ORDER BY views desc, last_viewed_on desc limit 0,10

  • Popular questions of class 11 Chemistry

SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='2' AND subId='9' AND ex_no!=0 AND status=1 and id!=2791 ORDER BY last_viewed_on desc limit 0,10

  • Recently Viewed Questions of Class 11 Chemistry

Comments

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

  • Answered by Ekta Mehta
  • 4 months ago

Taking Screenshots on your Samsung Galaxy M31s is very easy and quick.

Comment(s) on this Question


Important links

Quick Links

Resources

Support