SELECT * FROM question_mgmt as q WHERE id=2797 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=47 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Thermodynamics enthalpy of combustion of carbon to co2 nbsp is 3

Question:

Enthalpy of combustion of carbon to CO2 is -393.5 kJ mol-1. Calculate the heat released upon formation of 35.2 g of CO2 from carbon and dioxygen gas.

Answer:

Formation of CO2 from carbon and dioxygen gas can be represented as:

C(s) + O2(g)  → CO2(g)           ΔfH = -393.5 kJ mol-1

(1 mole = 44 g)

Heat released on formation of 44g CO2 = -393.5 kJ mol-1

\therefore Heat released on formation of 35.2 g CO2

= [ -393.5kJ mol-1  /  44g  ]  x  35.2g

= -314.8 kJ mol-1


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