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Class 11
Chemistry
Thermodynamics
the equilibrium constant for a reaction is 10 wha...

Question:
The equilibrium constant for a reaction is 10. What will be the value of ΔG⁰ ? R = 8.314 JK^–1 mol^–1, T = 300 K.

Answer:

From the expression, ΔG⁰= -2.303 RTlogK_eq

ΔG⁰for the reaction,

= (2.303) (8.314 JK^-1mol^-1) (300 K) log10

= -5744.14 Jmol^-1

= -5.744 kJ mol^-1

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Question:
The equilibrium constant for a reaction is 10. What will be the value of ΔG⁰ ? R = 8.314 JK^–1 mol^–1, T = 300 K.

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Question: The equilibrium constant for a reaction is 10. What will be the value of ΔG0 ? R = 8.314 JK–1 mol–1, T = 300 K.

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Question:
The equilibrium constant for a reaction is 10. What will be the value of ΔG⁰ ? R = 8.314 JK^–1 mol^–1, T = 300 K.