SELECT * FROM question_mgmt as q WHERE id=2805 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=2 AND subId=9 AND chapterId=47 and ex_no='1' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 11th chemistry Thermodynamics calculate the entropy change in surroundings when

Question:

Calculate the entropy change in surroundings when 1.00 mol of H2O(l) is formed under standard conditions. ΔfH0 = –286 kJ mol–1.

Answer:

It is given that 286 kJ mol-1of heat is evolved on the formation of 1 mol of H2O(l). Thus, an equal amount of heat will be absorbed by the surroundings.

qsurr = +286 kJ mol-1

Entropy change (ΔSsurr) for the surroundings =  qsurr / 7

= 286 kJ mol-1  / 298k

\therefore  ΔSsurr = 959.73 J mol-1K-1


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