A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box, find the probability that it bears (i) a two-digit number (ii) a perfect square number (iii) a number divisible by 5.
Total number of discs = 90
(i) A 2-digit number discs = 81
Probability of getting two-digit number = 81/90 = 9/10
(ii) A perfect square number disc = 9
Probability of getting a perfect square number disc
= 9/90 = 1/9
(iii) A number divisible by 5 = 18
Probability of getting numbered divisible by 5
= 18/90 = 1/5
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Welcome to the NCERT Solutions for Class 10 Mathematics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 18: A box contains 90 discs which are numbered from 1 to 90. If one disc is drawn at random from the box....
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