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Calculate the mass of sodium acetate (CH3COONa) required to make 500 m...

Calculate the mass of sodium acetate (CH | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Question:

Calculate the mass of sodium acetate (CH₃COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol^–1

Answer:

0.375 M solution of (CH₃COONa) = 0.375 moles(grams) of (CH₃COONa) dissolved in 1000 ml of solvent.

But according to question ,we have to make a 500 ml solution of (CH₃COONa)

∴Number of moles of sodium acetate in 500 mL

Molar mass of sodium acetate = 82.0245 g mole^–1 (Given)

∴ Required mass of sodium acetate = (82.0245 g mol^–1) (0.1875 mole)

= 15.38 g

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Comments

Ridham Patel
2020-05-29 18:45:51

Thank you

Tanu
2020-05-24 19:30:46

Thanks a lot

Adi
2019-07-21 07:53:18

Thanks for elaboration

Indranil
2019-07-09 15:09:38

Thanks

Saumya
2019-07-07 13:21:56

thanks for such good explanation

Prasoon
2019-06-30 14:40:45

Supriti try to love

ravi
2019-06-23 13:44:59

thnx

ravi
2019-06-23 13:44:11

thanx

Sahil
2019-06-18 17:24:38

Why we multi. 82.0245 with 0.1875 not divede

sakshi
2019-06-05 09:25:20

Thank you but I want it a little more briefly

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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 5: Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solut....

Calculate the mass of sodium acetate (CH | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

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