Density of a gas is found to be 5.46 g/d | Class 11 Chemistry Chapter States of Matter, States of Matter NCERT Solutions

Question:

Calculate the molecular mass of the following:
(i) H2O
(ii) CO2
(iii) CH4

Answer:

Molecules are made up of atoms & are  quite small, therefore the actual mass of a molecule cannot be detrmined.It is expressed as the relative mass.C-12 isotope is used to express the relative molecular masses of substances.Thus  molecular mass of a substance may be defined as: the average relative mass of its molecule as compared to the mass of carbon atom taken as 12 amu.

(i) H2O:

The molecular mass of water, H2O

= (2 × Atomic mass of hydrogen) + (1 × Atomic mass of oxygen)

= [2(1.0084) + 1(16.00 u)]

= 2.016 u + 16.00 u

= 18.016

= 18.02 u

(ii) CO2:

The molecular mass of carbon dioxide, CO2

= (1 × Atomic mass of carbon) + (2 × Atomic mass of oxygen)

= [1(12.011 u) + 2 (16.00 u)]

= 12.011 u + 32.00 u

= 44.01 u

(iii) CH4:

The molecular mass of methane, CH4

= (1 × Atomic mass of carbon) + (4 × Atomic mass of hydrogen)

= [1(12.011 u) + 4 (1.008 u)]

= 12.011 u + 4.032 u

= 16.043 u


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about States of Matter.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

Comments

  • Ash
  • 2019-11-10 11:55:59

Thanks


  • Vivek
  • 2019-09-29 05:57:37

Thanx


  • B ghosh
  • 2019-09-21 18:15:27

How can we compare the equations


  • Harshit Rathi
  • 2019-04-05 09:24:17

What is the use of 5.46 in this numerical


  • PB
  • 2019-02-19 13:22:03

Thanku ji


  • Sukhpal gill
  • 2018-10-27 07:04:05

Good


  • M Datta
  • 2017-12-17 09:56:59

Thanks


  • M Datta
  • 2017-12-17 09:56:31

In the last step that would be: (300×5.46)/(2×273) 🙂


  • Mehakpreet kaur
  • 2017-09-24 20:23:08

Thanks


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: Density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density ....