Density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density at STP?
For an ideal gas
Density ρ = p x M/ RT
F rom the given data,
5.46 = 2 x M/ 300 x R ………(1)
ALSO ρSTP = 1 x M/ 273 x R ………..(2)
FROM (1) & (2) ,WE GET
ρSTP = (1 x M/ 273 x R) x (300 x R/ 2 x M) x 5.46
= 300 x 5.46 / 273 X 2 = 3.00 g/dm3
Hence, the density of the gas at STP will be 3 g dm–3.
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: Density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density ....
Comments
Thanks
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How can we compare the equations
What is the use of 5.46 in this numerical
Thanku ji
Good
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In the last step that would be: (300Ã5.46)/(2Ã273) ð
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