Density of a gas is found to be 5.46 g/d | Class 11 Chemistry Chapter States of Matter, States of Matter NCERT Solutions

Question:

Density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density at STP?

Answer:

For an ideal gas

Density ρ = p x M/ RT

F rom the given data,

5.46 = 2 x M/ 300 x R    ………(1)

ALSO  ρSTP = 1 x M/ 273 x R    ………..(2)

FROM (1) & (2) ,WE GET

ρSTP =  (1 x M/ 273 x R)   x  (300 x R/ 2 x M) x 5.46

= 300 x 5.46 / 273 X 2 = 3.00 g/dm3

Hence, the density of the gas at STP will be 3 g dm–3.


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Comments

  • Ash
  • 2019-11-10 11:55:59

Thanks


  • Vivek
  • 2019-09-29 05:57:37

Thanx


  • B ghosh
  • 2019-09-21 18:15:27

How can we compare the equations


  • Harshit Rathi
  • 2019-04-05 09:24:17

What is the use of 5.46 in this numerical


  • PB
  • 2019-02-19 13:22:03

Thanku ji


  • Sukhpal gill
  • 2018-10-27 07:04:05

Good


  • M Datta
  • 2017-12-17 09:56:59

Thanks


  • M Datta
  • 2017-12-17 09:56:31

In the last step that would be: (300×5.46)/(2×273) 🙂


  • Mehakpreet kaur
  • 2017-09-24 20:23:08

Thanks


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: Density of a gas is found to be 5.46 g/dm3 at 27 °C at 2 bar pressure. What will be its density ....