Calculate the amount of carbon dioxide t | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Q4.

Calculate the amount of carbon dioxide that could be produced when

 

(i) 1 mole of carbon is burnt in air.

 

(ii) 1 mole of carbon is burnt in 16 g of dioxygen.

 

(iii) 2 moles of carbon are burnt in 16 g of dioxygen.

The chemical equation for the reaction is:

 

 

i) when 1 mole of carbon is burnt in 1 mole(32 g) of air(dioxygen) ,then according to chemical equation (1) 1mole(44 g) of carbon dioxide is produced.

 

ii) 32g of Oxygen upon heating gives CO2 = 44g

1 g of Oxygen upon heating gives CO2 = 44/32

 

Therefore 16 g of Oxygen upon heating gives CO2 = 44/32*16 = 22 g

 

(iii) According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.

 

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Important Questions & Answers

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

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This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What is the correct answer to: Calculate the amount of carbon dioxide that could be produced when   (i) 1 mole of carbon is burnt in air.   (ii) 1 mole of carbon is burnt in 16 g of dioxygen.   (iii) 2 moles of carbon are burnt in 16 g of dioxygen.?

The chemical equation for the reaction is:

 



 

i) when 1 mole of carbon is burnt in 1 mole(32 g) of air(dioxygen) ,then according to chemical equation (1) 1mole(44 g) of carbon dioxide is produced....

How do you solve Calculate the amount of carbon dioxide that could be produced when   (i) 1 mole of carbon is burnt in air.   (ii) 1 mole of carbon is burnt in 16 g of dioxygen.   (iii) 2 moles of carbon are burnt in 16 g of dioxygen. step by step?

Step-by-step explanation:
• The chemical equation for the reaction is:
•
•  
•
•

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Aayush kumar
Class · · , · Jan 06, 2020
Explain part 3 plzzzzzzz
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Pallavi
Class · · , · Sep 22, 2019
Explain part 3 clearly
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Tanika
Class · · , · Sep 16, 2019
Please explain the 3rd part
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Kalpana
Class · · , · Aug 28, 2019
Thanks
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Nahidha
Class · · , · Aug 22, 2019
Please explain third one
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Taeyhung
Class · · , · Aug 03, 2019
Answers of iii question is not elaborated
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Harsh Singh
Class · · , · Aug 02, 2019
cant u explain this in equation form
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Gu
Class · · , · Jul 30, 2019
Please give brief of part 3
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Akash
Class · · , · Jul 28, 2019
Please explain clear
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Kehkashan masroor siddiqui
Class · · , · Jul 20, 2019
Plz..explain 3rd part more clearly..
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