Calculate the amount of carbon dioxide that could be produced when
(i) 1 mole of carbon is burnt in air.
(ii) 1 mole of carbon is burnt in 16 g of dioxygen.
(iii) 2 moles of carbon are burnt in 16 g of dioxygen.
The chemical equation for the reaction is:
i) when 1 mole of carbon is burnt in 1 mole(32 g) of air(dioxygen) ,then according to chemical equation (1) 1mole(44 g) of carbon dioxide is produced.
ii) 32g of Oxygen upon heating gives CO2 = 44g
1 g of Oxygen upon heating gives CO2 = 44/32
Therefore 16 g of Oxygen upon heating gives CO2 = 44/32*16 = 22 g
(iii) According to the question, only 16 g of dioxygen is available. It is a limiting reactant. Thus, 16 g of dioxygen can combine with only 0.5 mole of carbon to give 22 g of carbon dioxide.
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 4: Calculate the amount of carbon dioxide that could be produced when (i) 1 mole of carbon....
Comments
Explain part 3 plzzzzzzz
Explain part 3 clearly
Please explain the 3rd part
Thanks
Please explain third one
Answers of iii question is not elaborated
cant u explain this in equation form
Please give brief of part 3
Please explain clear
Plz..explain 3rd part more clearly..