At 0°C, the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar. What is the molecular mass of the oxide?
Using the relationship of density (ρ) of the substance at temperature (T)
We have ρ = Mp/RT
or p = ρ RT/ M
For the given data if M is the molar mass of the gaseous oxide, we have
2 = ρ RT/ M ……………(1)
Also for nitrogen 5 = ρ RT/28 ………………….(2)
From (1) & (2), we have
5/2 = M/28
Or
M = 5 X 28/ 2 = 70g/mol
Hence, the molecular mass of the oxide is 70 g/mol.
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 4: At 0°C, the density of a certain oxide of a gas at 2 bar is same as that of dinitrogen at 5 bar.....
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M-mass P-pressure R-molar gas constant T-temperature