Calculate the wavelength of an electron | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Q20.

Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.

V= 2.05 x107 (given)

According to de Broglie’s equation,

Where, λ = wavelength of moving particle

m = mass of particle (9.10939 x 10-31)

v = velocity of particle

h = Planck’s constant (6.62 x 10-34)

Substituting the values in the expression of λ:

Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.

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Important Questions & Answers

What is the correct answer to: Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.?

V= 2.05 x107 (given)

According to de Broglie’s equation,



Where, λ = wavelength of moving particle

m = mass of particle (9.10939 x 10-31)

v = velocity of particle

h = Planck’s constan...

How do you solve Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1. step by step?

Step-by-step explanation:
• V= 2
• 05 x107 (given)

• According to de Broglie’s equation,

Why is this answer important for exams?

This question is important because it tests key concepts from the NCERT syllabus and is frequently asked in CBSE exams.

Which NCERT concept is used in this question?

This question is based on core NCERT concepts explained in the chapter and should be revised thoroughly before exams.

What common mistakes should be avoided in this question?

Students often lose marks by skipping steps, writing incomplete explanations, or misunderstanding keywords used in the question.

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Student Discussion

Saityapriyo Brahma
Class · · , · Oct 03, 2019
Thank u
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Saityapriyo Brahma
Class · · , · Oct 03, 2019
Thank u
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Vikrant
Class · · , · Aug 03, 2019
Thank you so much sir
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Amir
Class · · , · Apr 17, 2019
Thnk so much sir
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Janhavi Mishra
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Thanku so much sir
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Janhavi
Class · · , · Apr 02, 2019
Thank you so much sir
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Hemanand
Class · · , · Mar 20, 2019
Thanks for the answer
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Pelumi
Class · · , · Jan 30, 2019
Good Job
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Majid
Class · · , · Sep 04, 2018
Thanks
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Hima
Class · · , · Aug 19, 2018
Thanks a lot sir
Helped a lot to me
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