Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.
V= 2.05 x107 (given)
According to de Broglie’s equation,
Where, λ = wavelength of moving particle
m = mass of particle (9.10939 x 10-31)
v = velocity of particle
h = Planck’s constant (6.62 x 10-34)
Substituting the values in the expression of λ:
Hence, the wavelength of the electron moving with a velocity of 2.05 × 107 ms–1 is 3.548 × 10–11 m.
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 20: Calculate the wavelength of an electron moving with a velocity of 2.05 × 107 ms–1.....
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