(i) Calculate the total number of electr | Class 11 Chemistry Chapter Structure of Atom, Structure of Atom NCERT Solutions

Question:

(i) Calculate the total number of electrons present in one mole of methane.

(ii) Find
(a) the total number and
(b) the total mass of neutrons in 7 mg of 14C. (Assume that mass of a neutron = 1.675 × 10–27 kg).

(iii) Find
(a) the total number and
(b) the total mass of protons in 34 mg of NH3 at STP.

Will the answer change if the temperature and pressure are chang

Answer:

(i) Molecule of CH4 (methane) contains electron = 10
Therefore 1 mole (6.022 x 1023 atoms) contains electron = 6.022 x 1024

(ii)  a) 1g atom of 14C = 14g = 6.022 x 1023 atoms = 6.022 x 1024 x 8 neutrons
Thus 14g or 14000 mg have 6.022 x 1024 x 8 neutrons
Therefore 7 mg will have neutrons = 6.022 x 1024 x 8 / 14000 x 7 = 2.4088 x 1022

b) mass of 1 neutron = 1.675 x 10-27 kg
Therefore mass of 2.4088 x 1021 neutrons = 2.4088 x 1021 x 1.67 x 10-27 = 4.0347 x 10-6 kg

(iii)  a) 1 mol of NH3 = 17g NH3 = 6.022 x 1023 molecules of NH3 = (6.022x1023)(7 + 3) proton = 6.022 x 1024 protons
Therefore 34 mg i.e 0.034 g NH3 = 6.022 x 1024 x 0.034/1 = 1.2044 x 1022 protons

b) mass of 1 proton = 1.6726 x 10-27 kg
Therefore mass of 1.2044 x 1022 protons = (1.6726 x 10-27)(1.2044 x 1022) kg = 2.0145 x 10-5 kg

No, the answer will not change with change in temperature & pressure.


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Comments

  • NTIGURA JEAN LUTHER
  • 2019-11-22 15:08:20

i need questions and answers of chemistry 11 edition


  • Alok upadhyay
  • 2019-07-26 14:29:21

Easy method helpfull


  • corrector
  • 2019-05-07 17:21:54

multiplication is wrong


  • Priyanshu jain
  • 2018-07-18 22:27:00

Easy to learn Very helpful


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 2: (i) Calculate the total number of electrons present in one mole of methane. (ii) Find (a) the to....