At 450K, Kp= 2.0 × 1010/bar for the given reaction at equilibrium.
2SO2(g) + O2(g) ↔ 2SO3 (g)
What is Kc at this temperature ?
For the given reaction,
Δn = 2 - 3 =-1
T = 450 K
R = 0.0831 bar L bar K-1 mol-1
Kp = 2.0 × 1010 bar -1
We know that,
Kp = Kc (RT)Δn
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 10: At 450K, Kp= 2.0 × 1010/bar for the given reaction at equilibrium. 2SO2(g) + O2(g) ↔ 2....
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