==================>>>1==================>>>2==================>>>3==================>>>4 Class Question 7 : The motion of a body in s... Answer

The motion of a body in simple harmonic | Class 11 Physics Chapter Oscillations, Oscillations NCERT Solutions

Welcome to the NCERT Solutions for Class 11 Physics - Chapter Oscillations. This page offers a step-by-step solution to the specific question from Exercise 1, Question 7: . With detailed answers and explanations for each chapter, students can strengthen their understanding and prepare confidently for exams. Ideal for CBSE and other board students, this resource will simplify your study experience.

Question 7:

The motion of a body in simple harmonic motion is given by the displacement function,

x (t) = A cos (ωt + φ).

Given that at t = 0, the initial velocity of the body is ω cm/s and its initial position is 1 cm, calculate its initial phase angle and amplitude?

If in place of the cosine function, a sine function is used to represent the simple harmonic motion:

x = B sin (ωt + α),

calculate the body’s amplitude and initial phase considering the initial conditions given above. [Angular frequency of the particle is π/ s]

Answer:

Given,

Initially, at t = 0:

Displacement, x = 1 cm

Initial velocity, v = ω cm/sec.

Angular frequency, ω = π rad/s

It is given that:

x(t) = A cos( ωt + Φ) . . . . . . . . . . . . . . . . ( i )

1 = A cos( ω x 0 + Φ) = Acos Φ

A cos Φ = 1 . . . . . . . . . . . . . . . . ( ii )

Velocity, v = dx / dt

differentiating equation ( i ) w.r.t ‘t’

v = – Aωsin ( ωt + Φ)

Now at t = 0; v = ω and

=> ω = – Aωsin ( ωt + Φ)

1 = – A sin( ω x 0 + Φ) = -Asin(Φ)

Asin(Φ) = – 1 . . . . . . . . . . . . . . . . . . . . . . . ( iii )

Adding and squaring equations ( ii ) and ( iii ), we get:

A2(sin2 Φ + cos2 Φ) = 1 +1

thus, A =√2

Dividing equation ( iii ) by ( ii ), we get :

tan Φ = -1

Thus, Φ =3π/4 , 7π/4

Now if simple harmonic motion is given as :

x = B sin( ωt + α)

Putting the given values in the equation , we get :

1 = B sin ( ω x 0 + α)

Bsin α = 1 . . . . . . . . . . . . . . . . . . . . ( iv )

Also, velocity ( v ) = ω Bcos (ωt + α)

Substituting the values we get :

π = π B sin α

 B sin α = 1 . . . . . . . . . . . . . . . . . . . . ( v )

Adding and squaring equations ( iv ) and ( v ), we get:

B2[ sin2 α + cos2 α] =2

Therefore, B = √ 2

Dividing equation ( iv ) by equation ( v ), we get :

B sin α / B cos α = 1

tan α =1 = tan (π/4)

Therefore, α = π/4 , 5π/4, ......


Study Tips for Answering NCERT Questions:

NCERT questions are designed to test your understanding of the concepts and theories discussed in the chapter. Here are some tips to help you answer NCERT questions effectively:

  • Read the question carefully and focus on the core concept being asked.
  • Reference examples and data from the chapter when answering questions about Oscillations.
  • Review previous year question papers to get an idea of how such questions may be framed in exams.
  • Practice answering questions within the time limit to improve your speed and accuracy.
  • Discuss your answers with your teachers or peers to get feedback and improve your understanding.

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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 7: The motion of a body in simple harmonic motion is given by the displacement function, x (t) = A c....