A simple pendulum of length l and having a bob of mass M is suspended in a car. The car is moving on a circular track of radius R with a uniform speed v. If the pendulum makes small oscillations in a radial direction about its equilibrium position, what will be its time period?
The bob of the simple pendulum will experience centripetal acceleration because by the circular motion of the car and the acceleration due to gravity.
Acceleration due to gravity = g
Centripetal acceleration = v2 / R
Where,
v is the uniform speed of the car
R is the radius of the track Effective acceleration ( aaeff ) is given as :
aaeff = √ g2 +(v2/R)2
Time period, T = 2π √ l / aaeff
Where, l is the length of the pendulum
Therefore, Time period T
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 17: A simple pendulum of length l and having a bob of mass M is suspended in a car. The car is moving on....
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