A spring having with a spring constant 1200 N m-1 is mounted on a horizontal table as shown in Fig. A mass of 3 kg is attached to the free end of the spring. The mass is then pulled sideways to a distance of 2.0 cm and released.
Determine (i) the frequency of oscillations, (ii) maximum acceleration of the mass, and (iii) the maximum speed of the mass.
Given, Spring constant, k = 1200 N/m
Mass, m = 6 kg
Displacement, A = 4.0 cm = 0.04 cm
( i ) Oscillation frequency v = 1/T = 1/2π √k/m
Where,T = time period.
Therefore v =1/2×3.14 √1200/3 = 3.18m/s
Hence, the frequency of oscillations is 3.18 cycles per second.
( ii ) Maximum acceleration (a) = ω2 A
Where, ω = Angular frequency = √k/m
A = maximum displacement
Therefore, a = A( k/m )
a = 0.02 x (1200/3 ) = 8 m /s-2
( iii ) Maximum velocity, VMAX = ω A
= 0.02 X √1200/3
Therefore, VMAX = 0.4 m / s
Hence, the maximum velocity of the mass is 0.4 m/s.
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Welcome to the NCERT Solutions for Class 11 Physics - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 9: A spring having with a spring constant 1200 N m-1 is mounted on a horizontal table as shown in Fig. ....
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