SELECT * FROM question_mgmt as q WHERE id=1839 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=59 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Chemical Kinetics for the decomposition of azoisopropane to hexane a

Question:

For the decomposition of azoisopropane to hexane and nitrogen at 543 K, the following data are obtained.

t (sec) P(mm of Hg)
0 35.0
360 54.0
720 63.0

Calculate the rate constant

Answer:

The decomposition of azoisopropane to hexane and nitrogen at 543 K is represented by the following equation.

After time, t, total pressure, Pt = (Pº - p) + p + p

⇒ Pt = (Pº + p)

⇒ p = Pt  - Pº

therefore, Pº - p = Pº  - Pt  - Pº

= 2 Pº -  Pt

For a first order reaction,

k = 2.303/t  Log  Pº / Pº  - p

=   2.303/t  Log  Pº / 2 Pº  -  Pt

When t = 360 s, k = 2.303 / 360s log 35.0 / 2x35.0 - 54.0

= 2.175 × 10 - 3 s - 1

When t = 720 s, k = 2.303 / 720s log 35.0 / 2x35.0 - 63.0

= 2.235 × 10 - 3 s - 1

Hence, the average value of rate constant is

k = (2.175 × 10 - 3  + 2.235 × 10 - 3 ) / 2   s - 1

= 2.21 × 10 - 3 s - 1


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