SELECT * FROM question_mgmt as q WHERE id=1782 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=58 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Electrochemistry given the standard electrode potentials k k

Question:

Given the standard electrode potentials,

K+/ K = - 2.93V, 

Ag+/ Ag = 0.80V,

Hg2+ / Hg = 0.79V

Mg2+ / Mg = - 2.37 V,

Cr3+ / Cr = - 0.74V

Arrange these metals in their increasing order of reducing power.

Answer:

The lower the reduction potential, the higher is the reducing power. The given standard electrode potentials increase in the order of

K+/ K < Mg2+ / Mg < Cr3+ / Cr < Hg2+ / Hg < Ag+ / Ag.

Hence, the reducing power of the given metals increases in the following order:

Ag < Hg < Cr < Mg < K


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