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Class 11
Chemistry
Equilibrium
the ionization constant of phenol is 1 0 times 1...

Question:
The ionization constant of phenol is 1.0 × 10^–10. What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01M in sodium phenolate?

Answer:

Ionization of phenol:

C₆H₅OH + H₂O ↔ C₆H₅O^- + H₃O⁺

Initial Conc. 0.05 0 0

At equilibrium 0.05-x x x

Ka = [C₆H₅O^- x H₃O⁺] / C₆H₅OH

Ka = x x / 0.05-x

Ka = x² / 0.05-x

As the value of the ionization constant is very less, x will be very small. Thus,

we can ignore x in the denominator

Now, let α be the degree of ionization of phenol in the presence of 0.01 M C₆H₅ONa.

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Question:
The ionization constant of phenol is 1.0 × 10^–10. What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01M in sodium phenolate?

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Question: The ionization constant of phenol is 1.0 × 10–10. What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01M in sodium phenolate?

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Question:
The ionization constant of phenol is 1.0 × 10^–10. What is the concentration of phenolate ion in 0.05 M solution of phenol? What will be its degree of ionization if the solution is also 0.01M in sodium phenolate?