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the air is a mixture of a number of gases the maj...

Question:
The air is a mixture of a number of gases. The major components are oxygen and nitrogen with approximate proportion of 20% is to 79% by volume at 298 K. The water is in equilibrium with air at a pressure of 10 atm. At 298 Kif the Henry's law constants for oxygen and nitrogen are 3.30 x 10⁷ mm and 6.51 x 10⁷mm respectively, calculate the composition of these gases in water.

Answer:

Percentage of oxygen (O₂) in air = 20 %

Percentage of nitrogen (N₂) in air = 79%

Also, it is given that water is in equilibrium with air at a total pressure of 10 atm, that is, (10 × 760) mm Hg = 7600 mm Hg

Therefore, Partial pressure of oxygen, p_{o2 =}20/100 *7600

=1520 mm Hg

Partial pressure of nitrogen,p_N2= 79/100 *7600

= 6004 mmHg

Now, according to Henry's law:

p = K_H.x

For oxygen:

p_o2= K_H. x_O2

⇒x_O2= p_o2 / K_H

= 1520 / 3.30 X 10⁷

= 4.61 10^-5

For nitrogen:

p_N2 = K_H.x_N2

⇒x_N2= p_N2 / K_H

= 6004 / 6.51 x 10⁷

= 9.22 x 10^-5

Hence, the mole fractions of oxygen and nitrogen in water are 4.61 ×10 ^{- 5}and 9.22 × 10 ^{- 5}respectively.

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