SELECT * FROM question_mgmt as q WHERE id=1725 AND status=1 SELECT id,question_no,question,chapter FROM question_mgmt as q WHERE courseId=3 AND subId=9 AND chapterId=57 and ex_no='2' AND status=1 ORDER BY CAST(question_no AS UNSIGNED) CBSE Free NCERT Solution of 12th chemistry Solutions determine the amount of cacl2 i 2 47 dissolved

Question:

Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.

Answer:

We know that

π = i n/V RT

π = i w/MV iRT

w = πMV /  iRT     .......................(1)

Now we have given below values:

π =  0.75 atm

V = 2.5L

i = 2.47

T = (27+273) K = 300K

Here,

R = 0.0821L atm k-1 mol-1

M = 1x40 + 2x35.5

= 111 g/mol

Now putting the value in equation 1:

w =  0.75x111x2.5 / 2.47x0.0821x300

=3.42g

Hence, the required amount of CaCl2 is 3.42 g.


SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='9' AND ex_no!=0 AND status=1 and id!=1725 ORDER BY views desc, last_viewed_on desc limit 0,10
SELECT ex_no,question,question_no,id,chapter FROM question_mgmt as q WHERE courseId='3' AND subId='9' AND ex_no!=0 AND status=1 and id!=1725 ORDER BY last_viewed_on desc limit 0,10

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