Determine the empirical formula of an ox | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Question:

Calculate the molecular mass of the following:
(i) H2O
(ii) CO2
(iii) CH4

Answer:

Molecules are made up of atoms & are  quite small, therefore the actual mass of a molecule cannot be detrmined.It is expressed as the relative mass.C-12 isotope is used to express the relative molecular masses of substances.Thus  molecular mass of a substance may be defined as: the average relative mass of its molecule as compared to the mass of carbon atom taken as 12 amu.

(i) H2O:

The molecular mass of water, H2O

= (2 × Atomic mass of hydrogen) + (1 × Atomic mass of oxygen)

= [2(1.0084) + 1(16.00 u)]

= 2.016 u + 16.00 u

= 18.016

= 18.02 u

(ii) CO2:

The molecular mass of carbon dioxide, CO2

= (1 × Atomic mass of carbon) + (2 × Atomic mass of oxygen)

= [1(12.011 u) + 2 (16.00 u)]

= 12.011 u + 32.00 u

= 44.01 u

(iii) CH4:

The molecular mass of methane, CH4

= (1 × Atomic mass of carbon) + (4 × Atomic mass of hydrogen)

= [1(12.011 u) + 4 (1.008 u)]

= 12.011 u + 4.032 u

= 16.043 u


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Comments

  • Silima aktar
  • 2019-08-20 23:22:21

Why is mass dioxygen taken 16?


  • Swarnila
  • 2019-08-16 12:17:37

But the question said dioxygen


  • Vikasini
  • 2019-08-04 00:22:42

Excuse me actually the simplest whole number ratio should come Fe=1 & O=2 .why the answer is Fe=2 & O=3?


  • srushti
  • 2019-08-02 21:48:08

Correct ans sir


  • Tapaswini singh
  • 2019-07-30 10:13:46

But it's a dioxygen


  • Naivedhya
  • 2019-07-27 08:58:11

Why is mass of oxygen taken 16?


  • Unnati
  • 2019-07-22 22:20:34

Why to double the simplest whole number ratio


  • Uday thakur
  • 2019-07-21 17:22:42

Thank you


  • Nikhil Singh
  • 2019-07-21 11:36:18

Its gud


  • Zainab dharwala
  • 2019-07-10 09:04:16

I think they had double the simplest ratio than it become 2 and 3


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass.....