Determine the empirical formula of an ox | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Question:

Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass.

Answer:

Empirical formula of a compound may be defined as the formula which gives the simplest whole number ratio of the atoms of various elements present in one molecule of the compound.

 

Form the available data Percentage of iron = 69.9

 

Percentage of oxygen= 30.1 Total percentage of iron & oxygen= 69.9+30.1= 100%

 

Step 1 calculation of simplest whole number ratios of the elements

Element

Percentage

Atomic mass

Atomic ratio

Simplest ratio

Simplest whole no ratio

Fe

69.9

55.84

69.9/55.84=1.25

1.25= 1

2

O

30.1

16

30.1/16 = 1.88

1.88=1.5

3

Step 2 writing the empirical formula of the compound

 

The empirical formula of the compound = Fe2 O3

 

 


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Comments

  • Silima aktar
  • 2019-08-20 23:22:21

Why is mass dioxygen taken 16?


  • Swarnila
  • 2019-08-16 12:17:37

But the question said dioxygen


  • Vikasini
  • 2019-08-04 00:22:42

Excuse me actually the simplest whole number ratio should come Fe=1 & O=2 .why the answer is Fe=2 & O=3?


  • srushti
  • 2019-08-02 21:48:08

Correct ans sir


  • Tapaswini singh
  • 2019-07-30 10:13:46

But it's a dioxygen


  • Naivedhya
  • 2019-07-27 08:58:11

Why is mass of oxygen taken 16?


  • Unnati
  • 2019-07-22 22:20:34

Why to double the simplest whole number ratio


  • Uday thakur
  • 2019-07-21 17:22:42

Thank you


  • Nikhil Singh
  • 2019-07-21 11:36:18

Its gud


  • Zainab dharwala
  • 2019-07-10 09:04:16

I think they had double the simplest ratio than it become 2 and 3


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 3: Determine the empirical formula of an oxide of iron which has 69.9% iron and 30.1% dioxygen by mass.....