The equilibrium constant for a reaction is 10. What will be the value of ΔG0 ? R = 8.314 JK–1 mol–1, T = 300 K.
From the expression, ΔG0 = -2.303 RTlogKeq
ΔG0 for the reaction,
= (2.303) (8.314 JK-1mol-1) (300 K) log10
= -5744.14 Jmol-1
= -5.744 kJ mol-1
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Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 20: The equilibrium constant for a reaction is 10. What will be the value of ΔG0 ? R = 8.314....
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Thnku for the answerð