The following data are obtained when din | Class 11 Chemistry Chapter Some Basic Concepts of Chemistry, Some Basic Concepts of Chemistry NCERT Solutions

Question:

Calculate the molecular mass of the following:
(i) H2O
(ii) CO2
(iii) CH4

Answer:

Molecules are made up of atoms & are  quite small, therefore the actual mass of a molecule cannot be detrmined.It is expressed as the relative mass.C-12 isotope is used to express the relative molecular masses of substances.Thus  molecular mass of a substance may be defined as: the average relative mass of its molecule as compared to the mass of carbon atom taken as 12 amu.

(i) H2O:

The molecular mass of water, H2O

= (2 × Atomic mass of hydrogen) + (1 × Atomic mass of oxygen)

= [2(1.0084) + 1(16.00 u)]

= 2.016 u + 16.00 u

= 18.016

= 18.02 u

(ii) CO2:

The molecular mass of carbon dioxide, CO2

= (1 × Atomic mass of carbon) + (2 × Atomic mass of oxygen)

= [1(12.011 u) + 2 (16.00 u)]

= 12.011 u + 32.00 u

= 44.01 u

(iii) CH4:

The molecular mass of methane, CH4

= (1 × Atomic mass of carbon) + (4 × Atomic mass of hydrogen)

= [1(12.011 u) + 4 (1.008 u)]

= 12.011 u + 4.032 u

= 16.043 u


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Comments

  • Prakash
  • 2018-08-28 22:04:59

Thx


  • Satvir Singh
  • 2017-05-16 15:45:26

No it is given in the question itself that the ratio of dioxygrn is 16, 32 , 32, 80 so the whole no ratio with dinitrogen is 1:2:2:5


  • Rakshith
  • 2017-05-12 16:11:47

If we fix the mass of dinitrogen at 14 g, then masses of dioxygen will be 16 g, 32 g, 16 g, & 40 g. Then the ratio becomes 1:2:1:2.5. Is there any mismatch or i have understood wrong. Kindly clarify With regards Krishnaraj


Comment(s) on this Question

Welcome to the NCERT Solutions for Class 11 Chemistry - Chapter . This page offers a step-by-step solution to the specific question from Excercise 1 , Question 21: The following data are obtained when dinitrogen and dioxygen react together to form different compou....